X^2-4x=97

Solution for X^2-4x=97 equation:

X^2-4X=97

We move all terms to the left:

X^2-4X-(97)=0

a = 1; b = -4; c = -97;
Δ = b2-4ac
Δ = -42-4·1·(-97)
Δ = 404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{404}=\sqrt{4*101}=\sqrt{4}*\sqrt{101}=2\sqrt{101}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{101}}{2*1}=\frac{4-2\sqrt{101}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{101}}{2*1}=\frac{4+2\sqrt{101}}{2}
$